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Q.
The basic geometry and shape of $I_{3}^{-}$ are respectively:
NTA AbhyasNTA Abhyas 2022
Solution:
$X$ for $I _3^{-}=\frac{1}{2} 7+2-0+1=5$
Hybridization of $I$ in $I _3^{-}$is $sp ^3 d$.
Thus $I _3^{-}$has trigonal bipyramidal geometry with linear shape.