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  4. The base of an isosceles triangle is equal to 4 , the base angle is equal to 45°. A straigth line cuts the extension of the base at a point M at the angle θ where θ is acute and bisects the lateral side of the triangle which is nearest to M. The area 'A' of the quadrilateral which the straight line cuts off from given triangle is

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Q. The base of an isosceles triangle is equal to $4$ , the base angle is equal to $45^{\circ}$. A straigth line cuts the extension of the base at a point $M$ at the angle $\theta$ where $\theta$ is acute and bisects the lateral side of the triangle which is nearest to $M$.
The area '$A$' of the quadrilateral which the straight line cuts off from given triangle is

Straight Lines

Solution:

Correct answer is (d) $\frac{3+5 \tan \theta}{1+\tan \theta}$