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  4. The banking angle for a curved road of radius 490 m for a vehicle moving at 35 m s -1 is

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Q. The banking angle for a curved road of radius $490\, m$ for a vehicle moving at $35\, m\, s ^{-1}$ is

Laws of Motion

Solution:

Here, $v=35\, ms ^{-1}, r=490\, m$
$\therefore \tan \theta=\frac{v^{2}}{r g}=\frac{(35)^{2}}{490 \times 9.8}=0.25$
or $ \theta=\tan ^{-1}(0.25)$