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Physics
The back emf induced in a coil, when current changes from 1 ampere to zero in one milli-second, is 4 volts, the self inductance of the coil is
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Q. The back emf induced in a coil, when current changes from $1$ ampere to zero in one milli-second, is $4$ volts, the self inductance of the coil is
BITSAT
BITSAT 2010
A
1 henry
0%
B
4 henry
0%
C
$10^{-3}$ henry
33%
D
$4 \times10^{-3}$ henry
67%
Solution:
$e=-L \frac{d i}{d t}$
But $e=4\, V$ and $\frac{d i}{d t}=\frac{0-1}{10^{-3}}=-1/ 10^{-3}$
$\therefore \frac{-1}{10^{-3}}(-L)$
$=\Rightarrow L=4 \times 10^{-3}$ henry