Question

The average velocity of a freely falling body is numerically equal to half of the acceleration due to gravity. The velocity of the body as It reaches the ground is

• A. g
• B. $\frac{g}{2}$
• C. $\frac{g}{\sqrt{2}}$
• D. $\sqrt{2}g$

Answer 1

Answer: (A)

We have average velocity $=\frac{ g }{2}$
Since it is a free fall, average velocity, $v =\frac{ S }{ t }=\frac{\frac{1}{2} gt ^{2}}{ t }=\frac{ g }{2}$, where $t$ is the time
of descent and initial velocity is zero.
We know that for a free fall, velocity with which it reaches the ground: $V = gt$
where $t$ is time of descent.
Substituting the same in the above equation for average velocity:
$\frac{ V }{2}=\frac{ g }{2}$
$\therefore V = g$