Question

The average velocity of a body moving with uniform acceleration after travelling a distance of $3.06\, m$ is $0.34\, m s ^{-1}$. If the change in velocity of the body is $0.18\,m s ^{-1}$ during this time, its uniform acceleration is

• A. $0.01\, ms ^{-2}$
• B. $0.02\, m s ^{-2}$
• C. $0.03\, m s ^{-2}$
• D. $0.04\, m s ^{-2}$

Answer 1

Answer: (B)

Given. $v_{ av }=\frac{v+u}{2}=0.34$ and $v-u=0.18$
Solving these two equations,
we get $u=0.25\, ms ^{-1}, v=0.43\, ms ^{-1}$.
Given $s=3.06\, m$
Now use $v^{2}-u^{2}=2 a s$ to find $a=0.02\, ms ^{-2}$.