1. Tardigrade
  2. Question
  3. Physics
  4. The average translational kinetic energy of O2 (molar mass 32) molecules at a particular temperature is 0.048 eV. The translational kinetic energy of N2 (molar mass 28) molecules in eV at the same temperature is

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Q. The average translational kinetic energy of $O_2$ (molar mass $32$) molecules at a particular temperature is $0.048 \,eV$. The translational kinetic energy of $N_2$ (molar mass $28$) molecules in $eV$ at the same temperature is

BITSATBITSAT 2012

Solution:

Given,
$E _{ O _{2}}=0.048\, eV$
We know that,
Translational kinetic energy,
$E =\frac{3}{2} KT$
where, $k =$ Boltzmann constant
$T =$Temperature }
$\therefore E \propto T$
Since, the temperature is same for both oxygen and nitrogen
therefore, $E _{ O _{2}}= E _{ N _{2}}$
$\therefore E _{ N _{2}}=0.048 \,eV$