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Q. The average translational $K.E.$ in one millilitre volume of oxygen at $NTP$ is

NTA AbhyasNTA Abhyas 2020

Solution:

$KE_{trans}=\frac{3}{2}PV$
$\left(KE\right)_{trans}=\frac{3}{2}\left(\left(10\right)^{5}\right)\left(\left(10\right)^{- 6}\right)$
$KE_{trans}=0.15 \, J$