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Q.
The average power lost in pure capacitor in an $A.C$. circuit:
Rajasthan PMTRajasthan PMT 2004Alternating Current
Solution:
Average power of A.C. circuit
$P_{a v}=V_{ \text{rms }} \times I_{\text{rms }} \cos \phi$
If circuit contains only capacitor, then
$\phi =-\frac{\pi}{2}$
$\therefore \cos \phi =\cos \left(-\frac{\pi}{2}\right)=0 $
so, $ P_{a v} =0$