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Q. The average molar mass of chlorine is $35.5 \,g\,mol ^{-1}$. The ratio of ${ }^{35} Cl$ to ${ }^{37} Cl$ in naturally occurring chlorine is close to :

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Solution:

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Av. molar mass $=\frac{ n _{1} M _{1}+ n _{2} M _{2}}{\left( n _{1}+ n _{2}\right)}$

$35.5=\frac{ x \times 35+1 \times 37}{ x +1}$

$x =3$