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  4. The average energy-density of electromagnetic wave given by E=(50 N C- 1)sin(ω t - k x) will be nearly :-

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Q. The average energy-density of electromagnetic wave given by $E=\left(50 N C^{- 1}\right)sin\left(\omega t - k x\right)$ will be nearly :-

NTA AbhyasNTA Abhyas 2022

Solution:

Average energy density of electromagnetic wave
$U_{ av }=\frac{1}{2} \varepsilon_0 E_0^2=\frac{1}{2} \times\left(8.85 \times 10^{-12}\right) \times(50)^2$
$\approx 10^{-8} \quad J \quad m ^{-3}$