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Q. The average electric field of electromagnetic waves in certain region of free space is $9 \times 10^{-4}\, N\, C ^{-1}$. Then the average magnetic field in the same region is of the order of

Electromagnetic Waves

Solution:

$E=9 \times 10^{-4} \,N\, C ^{-1}$
For electromagnetic waves, $\frac{E}{B}=c$, speed of light in vacuum.
$\Rightarrow \frac{9 \times 10^{-4}}{B}=3 \times 10^{8}\, m \,s ^{-1}$ or $B=3 \times 10^{-12} \,T$