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Q. The average e.m.f. induced in a coil in which the current changes from$ 2$ ampere to $4$ ampere in $0.05$ second is $8$ volt. What is the self inductance of the coil?

Solution:

$e=-L \frac{d i}{d t} $
$\Rightarrow 8=L \frac{(4-2)}{0.05}$
$ \Rightarrow L=0.2\, H$