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  4. The average depth of Indian ocean is about 5000 m. What will be the percentage fractional compression of water at the bottom of the ocean, given that the bulk modulus of water is 3 × 109 Pa ⋅ g =9.8 m / s 2 (1 Pa =1 N / m 2)

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Q. The average depth of Indian ocean is about $5000 m$. What will be the percentage fractional compression of water at the bottom of the ocean, given that the bulk modulus of water is $3 \times 10^{9} Pa \cdot g =9.8 m / s ^{2}$
$\left(1 Pa =1 N / m ^{2}\right)$

Mechanical Properties of Solids

Solution:

$P=h \rho g=5000 \times 10^{3} \times 9.8$
$\therefore B=\frac{P}{\Delta V} \times V$
$\Rightarrow \frac{\Delta V}{V}$
$=\frac{P}{B}=\frac{5000 \times 10^{3} \times 9.8}{3 \times 10^{9}}$
$\therefore \frac{\Delta V}{V}=16333.3 \times 10^{-6}=1.6 \times 10^{-2}$
$\frac{\Delta V}{V} \times 100=1.6 \%$