1. Tardigrade
  2. Question
  3. Physics
  4. The average degree of freedom per molecule for a gas is 6. The gas performs 25 J of work when it expands at constant pressure. The heat absorbed by the gas is

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The average degree of freedom per molecule for a gas is $6$. The gas performs $25\,J$ of work when it expands at constant pressure. The heat absorbed by the gas is

JIPMERJIPMER 2014Kinetic Theory

Solution:

$\gamma = 1 + \frac{2}{f} = 1 + \frac{2}{6} = \frac{4}{3}$
$\frac{\Delta W}{\Delta Q}=\frac{\Delta Q - \Delta U}{\Delta Q} = 1-\frac{nC_{V} \Delta T}{nC_{P} \Delta T} $
$= 1 - \frac{1}{\gamma} = 1 -\frac{3}{4} =\frac{1}{4}$
$ \therefore \:\: \Delta Q = 4 \Delta W = 100 J$
$ \left( \because \frac{C_{P}}{C_{V}} = \gamma\right)$