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Chemistry
The atomic number of cobalt is 27. The EAN of cobalt in Na3 [Co(NO2)4Cl2] is
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Q. The atomic number of cobalt is $27$. The $EAN$ of cobalt in $Na_3 [Co(NO_2)_4Cl_2]$ is
KCET
KCET 2012
Coordination Compounds
A
35
11%
B
24
29%
C
36
46%
D
34
14%
Solution:
EAN of $Co$ in $Na _{3}\left[ Co \left( NO _{2}\right)_{4} Cl _{2}\right]$
$=$ Atomic number of Co \pm oxidation state of Co
$+$ number of $e^{-}$ taken from $- NO _{2}$ and $- Cl$
$=27+3+(4+2)=36$