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Q. The atomic number of cobalt is $27$. The $EAN$ of cobalt in $Na_3 [Co(NO_2)_4Cl_2]$ is

KCETKCET 2012Coordination Compounds

Solution:

EAN of $Co$ in $Na _{3}\left[ Co \left( NO _{2}\right)_{4} Cl _{2}\right]$

$=$ Atomic number of Co \pm oxidation state of Co

$+$ number of $e^{-}$ taken from $- NO _{2}$ and $- Cl$

$=27+3+(4+2)=36$