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Q. The atomic number of cerium $(Ce)$ is $58$. The correct electronic configuration of $Ce^{3+}$ ion is

WBJEEWBJEE 2015

Solution:

Atomic number of cerium $=58$
Electronic configuration of $Ce$
$=[ Xe ] 4 f^{2},\, 5 d^{0},\, 6 s^{2}$
Electronic configuration of $Ce ^{3+}$
$=[ Xe ] 4 f^{1}$