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Chemistry
The atomic number of cerium (Ce) is 58. The correct electronic configuration of Ce3+ ion is
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Q. The atomic number of cerium $(Ce)$ is $58$. The correct electronic configuration of $Ce^{3+}$ ion is
WBJEE
WBJEE 2015
A
$[Xe]4f^1$
B
$[Kr]4f^1$
C
$[Xe]4f^{13}$
D
$[Kr]4d^1$
Solution:
Atomic number of cerium $=58$
Electronic configuration of $Ce$
$=[ Xe ] 4 f^{2},\, 5 d^{0},\, 6 s^{2}$
Electronic configuration of $Ce ^{3+}$
$=[ Xe ] 4 f^{1}$