1. Tardigrade
  2. Question
  3. Physics
  4. The atomic masses of 12 H and 24 H are 2.0141 u and 4.0026 u respectively. Taking the velocity of light in vacuum to be 2.998 × 108 m s -1 , calculate the amount of energy (in J) liberated when two moles of 12 H undergo a fusion to form one mole of 24 H. [ u =1.66057 × 10-27 kg ]

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The atomic masses of ${ }_{1}^{2} H$ and ${ }_{2}^{4} H$ are $2.0141 \quad u$ and $4.0026 u$ respectively. Taking the velocity of light in vacuum to be $2.998 \times 10^{8} m s ^{-1}$ , calculate the amount of energy (in J) liberated when two moles of ${ }_{1}^{2} H$ undergo a fusion to form one mole of ${ }_{2}^{4} H$. $\left[ u =1.66057 \times 10^{-27} kg \right]$

NTA AbhyasNTA Abhyas 2022

Solution:

$2{ }_{1}^{2} H \rightarrow{ }_{2}^{4} H +$ Energy
Mass defect $=2 \times 2.0141-4.0026=0.0256 amu$
$ \begin{array}{l} \therefore \quad \Delta E =\Delta m \times c ^{2} \\ =0.0256 \times 1.66057 \times 10^{-27} \times 6.02 \times 10^{23} \times\left(2.998 \times 10^{8}\right)^{2} \\ =2.3 \times 10^{12} J \end{array} $