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Q.
The atomic mass and atomic number of lead are $208$ and $82$ . The atomic mass and atomic number of bismuth are $209$ and $83$ . The neutron/proton ratio in an atom
Structure of Atom
Solution:
${ }_{82} Pb ^{208} ; p=82 ; n=208-82=126$
${ }_{83} Bi ^{209} ; p=83 ; n=209-83=126$
$n / p$ for $Pb =\frac{126}{82}=1.53$
$n / p$ for $Bi =\frac{126}{83}=1.51$
$\therefore \frac{n}{p}$ for $Pb >\frac{ n }{ p }$ for $Bi$