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Q.
The area of the triangle formed by the mid points of sides of the triangle whose vertices are $(2,1)$, $(-2,3),(4,-3)$ is -
Straight Lines
Solution:
Area of the triangle formed by joining the mid points of the sides of the triangle $=\frac{1}{4}$ (area of the triangle)
$=\frac{1}{4} \times \frac{1}{2}\begin{vmatrix} 2 & 1 & 1 \\ -2 & 3 & 1 \\ 4 & -3 & 1
\end{vmatrix} $
$=\frac{1}{4} \times 6=1.5 \text { sq.units }$
