Q. The area of the region enclosed between the parabolas $y ^{2}=2 x -1$ and $y ^{2}=4 x -3$ is
Solution:
Required area $=2 \int\limits_{0}^{1}\left(\frac{ y ^{2}+3}{4}-\frac{ y ^{2}+1}{2}\right) dy$
$=2 \int\limits_{0}^{1} \frac{1-y^{2}}{4} d y=\frac{1}{2}\left|y-\frac{y^{3}}{3}\right|_{0}^{1}=\frac{1}{3}$
