1. Tardigrade
  2. Question
  3. Mathematics
  4. The area of the region A = [(x, y): 0 ≤ y ≤ x|x|+1 and -1 ≤ x ≤ 1] in sq. units is :

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. The area of the region
$A = [(x, y): 0 \leq y \leq x|x|+1$ and $-1 \leq x \leq 1]$ in sq. units is :

JEE MainJEE Main 2019Application of Integrals

Solution:

The graph is a follows
$\int^{0}_{-1} \left(-x^{2} +1\right)dx + \int^{1}_{0} \left(x^{2} +1\right)dx = 2 $

Solution Image