Thank you for reporting, we will resolve it shortly
Q.
The area of the quadrilateral formed by the tangents and normals at the extremities of the latus rectum of the parabola $y^{2}-4y+4+12x=0$ is
NTA AbhyasNTA Abhyas 2022
Solution:
$\left(y - 2\right)^{2}=-12x$
The quadrilateral is a square with diagonal length
$=12$
$\therefore $ Area $=\frac{1}{2}\times 12\times 12=72$ sq. units