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Q. The area of hysteresis loop of a material is equivalent to $250\, J / m ^{3}$. When $10 \,kg$ material is magnestized by an alternating field of $50 \,Hz$, then energy lost in one hour will be $\beta$ joule. Find $\frac{\beta}{1000}$. (Density of material is $7.5 \,g / cm ^{3}$ )

Magnetism and Matter

Solution:

Energy lost in $1$ hour
$=$ Area $\times$ Volume $\times$ Time $\times$ Frequency
$=\frac{250 \times 10 \times 3600 \times 50}{7500}$
$=6 \times 10^{4} \,J$