Question

The area of figure bounded by $y=e^{x}, y=e^{-x}$ and the straight line $x=1$ is

• A. $\left(e+\frac{1}{e}\right)$ sq unit
• B. $\left(e-\frac{1}{e}\right)$ sq unit
• C. $\left(e+\frac{1}{e}-2\right)$ sq unit
• D. $\left(e+\frac{1}{e}+2\right)$ sq unit

Answer 1

Answer: (C)

Required area $=\int\limits_{0}^{1}\left(e^{x}-e^{-x}\right) d x$
$=\left[e^{x}+e^{-x}\right]_{0}^{1}$

$=\left(e+\frac{1}{e}-2\right)$ sq unit