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Q. The area enclosed by the curves $y=\cos x, y=1+\sin 2 x$ and $x=\frac{3 \pi}{2}$ as $x$ varies from $0$ to $\frac{3 \pi}{2}$, is -

Application of Integrals

Solution:

Correct answer is (c) $2+\frac{3 \pi}{2}$