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Q. The area bounded by $y =x^{2} +3$ and $y =2x+3$ is

KEAMKEAM 2015Application of Integrals

Solution:

Required area
$=\int_{0}^{2}(2 x+3)-\left(x^{2}+3\right) d x$
image
$=\int_{0}^{2}\left(2 x-x^{2}\right) d x$
$=\left[\frac{2 x^{2}}{2}-\frac{x^{3}}{3}\right]_{0}^{2}$
$=\left[4-\frac{8}{3}\right]=\frac{4}{3}$ sq units