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Q.
The area bounded by the curves $x=y^{2}$ and $x=\frac{2}{1+y^{2}}$ is
Application of Integrals
Solution:
Solving curves, we get
point of intersections $(1, \pm 1)$.
Required area
$=2 \int\limits_{0}^{1}\left(\frac{2}{1+y^{2}}-y^{2}\right) d y=\pi-\frac{2}{3} .$
