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  4. The approximate molarity of a solution in mol L -1 that contains 13.50 g of NaCl dissolved in 452 mL of water is

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Q. The approximate molarity of a solution in $mol \,L ^{-1}$ that contains $13.50\,g$ of $NaCl$ dissolved in $452 \,mL$ of water is

TS EAMCET 2019

Solution:

Given,

Mass of $NaCl =13.5 \,g$

Volume of solution $=452\,mL$

Molarity of solution (M) $=\frac{\text { Mass of } NaCl }{\text { Molar mass of } NaCl } \times \frac{1}{\text { Volume of solution in (L) }}$

$M=\frac{13.50}{58.5} \times \frac{1000}{452} \,\,mol / L \Rightarrow M=0.51\,\,mol / L$