Question

The apparent weight of a person of mass $m$ in an elevator is $2 m g .$ The elevator is moving

• A. up with an acceleration of $\frac{g}{2}$
• B. up with an acceleration of $g$
• C. up with an acceleration of $2 g$
• D. down with an acceleration of $g$

Answer 1

Answer: (B)

Apparent weight is the normal force $N$ experienced by the person.
$N-m g=m a ; N=m(g+a)$
Here $N=2 m g \Rightarrow 2 m g=m g+m a$
or $a=g$