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Q.
The apparent depth of an object $O$ from $AB$ is
NTA AbhyasNTA Abhyas 2020Ray Optics and Optical Instruments
Solution:
Apparent depth $d$ is given by
$\Rightarrow d=\frac{t_{1}}{\mu _{1}}+\frac{t_{2}}{\mu _{2}}$
$\Rightarrow d=\frac{4}{1.4}+\frac{5}{1.5}=2.857+3.333$
$\Rightarrow d=6.190cm$
