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Q. The anodic half-cell of lead-acid battery is recharged unsing electricity of $0.05$ Faraday. The amount of $\ce{PbSO_4}$ electrolyzed in g during the process in : (Molar mass of $\ce{PbSO_4 = 303 \; g \; mol^{-1}}$)

JEE MainJEE Main 2019Electrochemistry

Solution:

A) $\underset{0.05 / 2 \text { mode }}{ PbSO _{4}}+2 OH -\rightarrow PbO _{2}+ H _{2} SO _{4}+\underset{0.05 F }{2 e^{-}}$
B) $\underset{0.05 / 2 \text { mole }}{ PbSO _{4}}+\underset{0.05 F }{ }+2 H ^{+} \rightarrow Pb (s)+ H _{2} SO _{4}$
$n_{T}\left( PbSO _{4}\right)=\frac{0.05}{2}$ mole
$ m_{ PSO _{4}}=\frac{0.05}{2} \times 303=7.6 gm $