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Q. The angular momentum of an electron in an orbit is quantized because it is a necessary condition for the compatibility with

Atoms

Solution:

$m v r=\frac{n h}{2 \pi} $
$\therefore \frac{h}{m v}=\frac{(2 \pi r)}{n}$
$\frac{h}{m v}=$ de Broglie wavelength