Question

The angle of polarisation for any medium is $60o$ . The criticle angle for same medium at air interface will be:-

• A. $\left(sin\right)^{- 1}\left(\frac{1}{\sqrt{3}}\right)$
• B. $\left(sin\right)^{- 1}\left(\right.\sqrt{3}\left.\right)$
• C. $\left(cos\right)^{- 1}\left(\right.\sqrt{3}\left.\right)$
• D. $\left(cos\right)^{- 1}\left(\frac{1}{\sqrt{3}}\right)$

Answer 1

Answer: (A)

$\mu =tani_{p}=\sqrt{3}$ $\Rightarrow $ $\left(\theta \right)_{c}=\left(sin\right)^{- 1}\left(\frac{1}{\mu }\right)$ $\Rightarrow $ $\left(\theta \right)_{c}=\left(sin\right)^{- 1}\left(\frac{1}{\sqrt{3}}\right)$ .