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Q. The angle of minimum deviation for a prism is $40^{\circ} $ and the angle of the prism is $60^{\circ} $ . The angle of incidence in this position will be

Delhi UMET/DPMTDelhi UMET/DPMT 2008Ray Optics and Optical Instruments

Solution:

Angle of incidence $i=\frac{A+\delta_{m}}{2}$
$=\frac{40^{\circ}+60^{\circ}}{2}=50^{\circ}$