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  4. The angle between the asymptotes of the hyperbola x2 - 3y2 = 12 is

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Q. The angle between the asymptotes of the hyperbola $x^2 - 3y^2 = 12$ is

COMEDKCOMEDK 2007Conic Sections

Solution:

We have $x^2 - 3y^2 = 12 \Rightarrow \:\:\: \frac{x^{2}}{12} - \frac{y^{2}}{4} = 1 $
Angle between assymptotes is given by $2\tan^{-1} \left(\frac{b}{a}\right) = 2 \times30^{\circ} = 60^{\circ}$