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Physics
The angle between pass axis of polarizer and analyser is 45°. The percentage of polarized light passing through analyser is
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Q. The angle between pass axis of polarizer and analyser is $45^{\circ}$. The percentage of polarized light passing through analyser is
Wave Optics
A
$75\%$
7%
B
$25\%$
25%
C
$50\%$
54%
D
$100\%$
14%
Solution:
Given,
$\theta=45^{0}$
By malus law,
$I \propto \cos ^{2} \theta$
$I \propto\left(\cos 45^{0}\right)^{2}$
$I \propto\left(\frac{1}{\sqrt{2}}\right)^{2}$
$I \propto(0.5)$
The percentage of polarized light passing through analyzer is $50 \%$.