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Mathematics
The angle between a normal to the plane 2x - y + 2z - 1 = 0 and the z-axis is
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Q. The angle between a normal to the plane $2x - y + 2z - 1 = 0$ and the z-axis is
Introduction to Three Dimensional Geometry
A
$\cos^{-1}\left(\frac{1}{3}\right)$
22%
B
$\sin^{-1}\left(\frac{2}{3}\right)$
31%
C
$\cos^{-1}\left(\frac{2}{3}\right)$
36%
D
$\sin^{-1}\left(\frac{1}{5}\right)$
11%
Solution:
d.r.s of the normal is (2, -1, 2)
d.r.s of z-axis is (0, 0, 1)
$\cos \theta = \left(\frac{2.0 + \left(-1\right).0 + \left(2\right)\left(1\right)}{\sqrt{2^{2} + 1^{2} +2^{2}} \sqrt{0^{2} + 0^{2} +1}}\right) = \frac{2}{3}$
$ \Rightarrow \, \, \, \theta$ = $\cos^{-1} \left(\frac{2}{3}\right)$