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Q.
The amount of zinc required to produce $224\, mL$ of $H_2$ at STP on treatment with dilute $H_2 SO_4$ will be(Zn =65)
AIPMTAIPMT 1996Some Basic Concepts of Chemistry
Solution:
$Zn + H _{2} SO _{4}(due) \longrightarrow Zn SO _{4}+ H _{2}$
I mole of zn react to give 1 mole of hydroge
$220\,4 ml$ of $H _{2}$
no of mole $= \frac{v at STP(ml)}{22400}$
$= \frac{224}{22400} =\frac{1}{100}$ mole
no of moles $= \frac{\text{mass}}{\text{atomic mass}}$
$=\frac{1}{100}mole =\frac{\text{mass}}{65\,g/mole}$
mass $= 0.65\,g$