Thank you for reporting, we will resolve it shortly
Q.
The amount of zinc required to produce $1.12\, ml$ of $H _{2}$ at STP on treatment with dilute $HCl$ will be
Some Basic Concepts of Chemistry
Solution:
$\underset{1 moL}{Zn} +2 HCl \longrightarrow \underset{22.4\,L = 22400\,ml}{ZnCl _{2}+ H _{2}( g )}$
$224000\, ml$ of $H _{2}$ gas is produced from $Zn =65\, g$
$1.12\, ml$ of $H _{2}$ gas is produced from
$Zn =\frac{65}{22400} \times 1.12\, g$
$=3.25 \times 10^{-3} g$
i.e., $32.5 \times 10^{-4} g$