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Chemistry
The amount of zinc (at. wt. = 65) necessary to produce 224 ml of H2 by the reaction with an acid will be
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Q. The amount of zinc (at. wt. = 65) necessary to produce $224\, ml$ of $H_2$ by the reaction with an acid will be
AIIMS
AIIMS 1995
A
6.5 gm
B
0.065 gm
C
7.5 gm
D
0.65 gm
Solution:
$Zn + H_{2}SO_{4} \to ZnSO_{4} + H_{2}$
$65 \,g$ Zn will give 22.4 litre of $H_{2}$ at STP
$\Rightarrow \, 224 \,ml $ of $H_{2}$ corresponds to $\frac{65}{22400}\times224$
$= 0.65 \,g \,Zn$