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Q. The amount of work done in an adiabatic expansion from temperature $T$ to $T_{1}$ is

Thermodynamics

Solution:

$\Delta Q=\Delta U+\Delta W$, but $\Delta Q=0$ for adiabatic process.
$\Rightarrow \Delta W=-\Delta U=-n C_{\nu}\left(T_{1}-T\right)=\frac{n R\left(T-T_{1}\right)}{\gamma-1}$