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  4. The amount of urea to be dissolved in 500 cc of water (K=1.86° C ) to produce a depression of 0.186° C in the freezing point is :

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Q. The amount of urea to be dissolved in $500\, cc$ of water $\left(K=1.86^{\circ} C \right)$ to produce a depression of $0.186^{\circ} C$ in the freezing point is :

ManipalManipal 2006Solutions

Solution:

We know that,
w (mass of solute) $=\frac{m \times \Delta T_{f} \times W}{1000 \times K_{f}}$
m=mol. wt. of urea (60)
$\Delta T_{f}=0.186^{\circ} C$
$K_{f}=1.86^{\circ}, W=500\, g$
$=\frac{60 \times 0.186 \times 500}{1000 \times 1.86}$
$=3\, g$