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Q. The amount of sugar $(C_{12}H_{22}O_{11})$ required to prepare $2\, L$ of its $0.1\, M$ aqueous solution is :

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Solution:

Molarity $= \frac{\left(n\right)_{\text{solute}}}{V_{\text{solution}} \left(\text{in} \text{lit}\right)} $
$ 0.1 = \frac{wt. /342}{2} $
$wt\left(C_{12}H_{22}O_{11}\right) = 68.4\, \text{gram} $