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  4. The amount of ice that will separate out on cooling a solution containing 45 g of ethylene glycol in 250 g water to -8.3° C is (Kf. of .H 2 O =1.86° mol -1 kg )

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Q. The amount of ice that will separate out on cooling a solution containing $45 \,g$ of ethylene glycol in $250 \,g$ water to $-8.3^{\circ} C$ is $\left(K_{f}\right.$ of $\left.H _{2} O =1.86^{\circ} \,mol ^{-1} kg \right)$

Solutions

Solution:

$w_{1}=$ solute $=50 \,g$ ethylene glycol

$\frac{w_{1}}{m_{1}}=\frac{45}{62} mol$

Solvent required to maintain this amount $=w_{2} g$

$\Delta T_{f}=8.3^{\circ}$

$ \therefore \Delta T_{f}=\frac{1000 w_{1} K_{f}}{m_{1} w_{2}} $

$ \therefore w_{2}=\frac{1000 w_{1} K_{f}}{m_{1} \Delta T_{f}}$

$=\frac{1000 \times 45 \times 1.86}{62 \times 8.3}=162.6 \,g $

Actual $ H _{2} O $ taken $=250\, g $

Thus, ice formed $=250-162.6=87.4 \,g$