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Q. The amount of heat required to change 1 g $ (0{}^\circ C) $ of ice into water of $ 100{}^\circ C, $ is

MGIMS WardhaMGIMS Wardha 2012

Solution:

Heat required to convert $ 0{}^\circ C $ of ice in water $ =mL $ (L = latent heat) Now, heat required to rise the temperature of water from $ 0{}^\circ C $ to $ 100{}^\circ C $ . $ =ms\Delta t $ where $ s= $ specific heat. $ \Delta t= $ temperature difference. Total heat $ =mL+ms\Delta t $ $ =1\times 80+1\times 1\times (100-0) $ $ =180cal $