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  4. The amount (in mol) of bromoform (CHBr3) produced when 1.0 mole of acetone reacts completely with 1.0 mole of bromine in the presence of aqueous NaOH is

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Q. The amount (in mol) of bromoform $(CHBr_3)$ produced when $1.0$ mole of acetone reacts completely with $1.0$ mole of bromine in the presence of aqueous $NaOH$ is

KVPYKVPY 2018

Solution:

$\underset{\text{Acetone}}{CH_3 - \underset{\overset{||}{O}}{C} - CH_3} + 3Br_2 + 4NaOH$
$\to CH_3\overset{\underset{||}{O}}{C}\overset{-}{ON}\overset{+}{a} + 3NaBr + 3H_2O + CHBr_3$
$3$ moles of bromine produces $1$ mole of $CHBr_{3}$.
$\therefore 1$ mole of bromine produces $\frac{1}{3}$mole of $CHBr_{3}$.