Question

The ammonia evolved from the treatment of $0.30\, g$ of an organic compound for the estimation of nitrogen was passed in $100 \,mL$ of $0.1\, M$ sulphuric acid. The excess of acid required $20 \,mL$ of $0.5 \,M$ sodium hydroxide solution for complete neutralization. The percentage nitrogen in the organic compound is(Report the answer in the nearest integer)

Answer 1

Equivalents of $NH_3$ evolved
$= \frac{1 0 0 \times 0 \cdot 1 \times 2}{1 0 0 0} - \frac{2 0 \times 0 \cdot 5}{1 0 0 0} = \frac{1}{1 0 0}$
Percent of nitrogen in the unknown organic compound
$= \frac{1}{1 0 0} \times \frac{1 4}{0. 3} \times 1 0 0 = 4 6 . 67$ $\cong$ $47$