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Q.
The acceleration of electron in the first orbit of a hydrogen atom is (where the symbols have their usual meanings)
NTA AbhyasNTA Abhyas 2022
Solution:
From $mvr=\frac{n h}{2 \pi },v=\frac{n h}{2 \pi m r}$
For the first Bohr orbit, $n=1$
Acceleration, $a=\frac{v^{2}}{r}=\frac{n^{2} h^{2}}{4 \left(\pi \right)^{2} m^{2} r^{2} \left(\right. r \left.\right)}=\frac{h^{2}}{4 \left(\pi \right)^{2} m^{2} r^{3}}$