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Q.
The acceleration of a particle traveling along a straight line is shown in the figure. The maximum speed of the particle is
Solution:
Maximum speed is at $t=8 \,\sec$
$v$ at $t=8 \,\sec$ is given by are under curve $O A B C$.
Max. speed $=\frac{1}{2}(A B+O C) \times B C $
$=\frac{1}{2} \times(12) \times 5=30 \,ms ^{-1}$